[Date Index] [Thread Index] [Author Index]

Partitioning a list into unequal partitions

• To: mathgroup at smc.vnet.net
• Subject: [mg47454] Partitioning a list into unequal partitions
• From: "DIAMOND Mark R." <dot at dot.dot>
• Date: Tue, 13 Apr 2004 06:26:07 -0400 (EDT)
• Sender: owner-wri-mathgroup at wolfram.com

Could someone please show me a simple (non-procedural) way of partitioning a
list into 1,2,3 ... n disjoint sublists, where the length of the list is
guaranteed to be correct (i.e. n*(n+1)/2)

I can't see a way, and yet I'm sure there *must* be a one-liner using Fold.

Cheers

Mark R. Diamond

• Follow-Ups:
  • Re: Partitioning a list into unequal partitions
    • From: Andrzej Kozlowski <akoz@mimuw.edu.pl>