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MathGroup Archive 2004

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Re: number of switches

  • To: mathgroup at smc.vnet.net
  • Subject: [mg47506] Re: [mg47479] number of switches
  • From: Tomas Garza <tgarza01 at prodigy.net.mx>
  • Date: Thu, 15 Apr 2004 03:39:10 -0400 (EDT)
  • References: <200404141116.HAA27212@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

It's hard to say which is the "easiest". This one does the job:

In[1]:=
digs = Table[Random[Integer, {0, 1}], {10}]
Out[1]=
{0, 1, 0, 1, 0, 1, 0, 0, 0, 1}

In[2]:=
Length[Split[digs]] - 1
Out[2]=
7

Tomas Garza
Mexico City
----- Original Message ----- 
From: "fake" <fake at fake.it>
To: mathgroup at smc.vnet.net
Subject: [mg47506] [mg47479] number of switches


> Consider the lists {1,1,0,1} and {1,1,0,0},{1,0,1,0,1}.
> The first sequence (1101) switches 2 times (#2digit~#3digit,
> #3digit~#4digit}, the second (1100) 1 time, the third 10101 4 times.
> 
> I have the following problem.
> Consider a list of binary digits. Which is the easiest way to count the
> number of switches of the list (using Mathematica commands)?
> 
> 


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