[Date Index]
[Thread Index]
[Author Index]
another bug...
*To*: mathgroup at smc.vnet.net
*Subject*: [mg47651] another bug...
*From*: Enrique Zeleny <ezeleny at fismat1.fcfm.buap.mx>
*Date*: Tue, 20 Apr 2004 03:19:05 -0400 (EDT)
*Sender*: owner-wri-mathgroup at wolfram.com
Hi,
In[1]:= expr = FunctionExpand[Cos[Pi/22]];
The next input doesn't work in 5.0, the expression that I want to replace
by a appears many times in expr
In[2]:= expr /. (1/2)*(-1 + Sqrt[5]) + I*Sqrt[2 - (1/2)*(-1 - Sqrt[5])] -> a
only works doing this
In[3]:= expr //. (1/2)*(-1 + Sqrt[5]) + I*Sqrt[2 - (1/2)*(m_)] -> a
If you look at FullForm
In[4]:= FullForm[(1/2)*(-1 + Sqrt[5]) + I*Sqrt[2 - (1/2)*(-1 - Sqrt[5])]]
Out[4]:= Plus[Times[Rational[1, 2], Plus[-1, Power[5, Rational[1, 2]]]],
Times[Complex[0, 1],
Power[Plus[2, Times[Rational[1, 2], Plus[1, Power[5, Rational[1, 2]]]]],
Rational[1, 2]]]]
but if you copy and paste the result of expr and you use //.
(1/2)*(Sqrt[5] - 1) + I*Sqrt[(1/2)*(Sqrt[5] + 1) + 2] -> a to replace works well!!!
In Version 4.1 only this works well (but not in 5.0), but the expression
that appears many times is written with +'s
In[2]:= expr //. (1/2)*(-1 + Sqrt[5]) + I*Sqrt[2 + (1/2)*(1 + Sqrt[5])] ->
a
If you copy and paste the result of expr and you use only /. instead of
//. to replace (1/2)*(-1 + Sqrt[5]) + I*Sqrt[2 + (1/2)*(1 + Sqrt[5])] ->a
works fine!!!
Clearly the problem is recognizing
- (1/2)*(-1 - Sqrt[5])
Enrique Zeleny
Universidad Autonoma de Puebla
Mexico
Prev by Date:
**How to convert a flat scan of a 3D object, into a 3D picture in cylindrical coordinates?**
Next by Date:
**RE: Kernel crash?**
Previous by thread:
**Re: How to convert a flat scan of a 3D object, into a 3D picture in cylindrical coordinates?**
Next by thread:
**Re: another bug...**
| |