[Date Index]
[Thread Index]
[Author Index]
Re: Parametric Plot
*To*: mathgroup at smc.vnet.net
*Subject*: [mg47789] Re: Parametric Plot
*From*: "Ronny Mandal" <ronnyma at student.matnat.uio.no>
*Date*: Tue, 27 Apr 2004 04:46:32 -0400 (EDT)
*Organization*: University of Oslo, Norway
*References*: <c6icih$6nl$1@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
"Bill Rowe" <readnewsciv at earthlink.net> wrote in message
news:c6icih$6nl$1 at smc.vnet.net...
> On 4/25/04 at 5:13 AM, ronnyma at student.matnat.uio.no (Ronny Mandal)
> wrote:
>
> >I'm trying to print the curve x=sin(t), y=cos(t) ,x+y=1 on
> >Mathematica 5, student version. Ican come up with :
>
> >ParametricPlot[{Sin[t], Cos[t]}, {t, 0, 2*[Pi]}] and this yields
> >what I want. Any suggestions on how I can draw the same curve
> >non-parametric?
>
> I am a bit puzzled. You indicate ParametricPlot[{Sin[t], Cos[t]}, {t, 0,
2*[Pi]}] does what you want. This would be a circle centered at the origin.
But in your initial statement you add another condition x + y = 1. This
would be a line. Did you mean this condition to be x^2 + y^2 = 1 instead of
what you posted?
>
> If the question is what other methods are available to plot a unit circle,
then you could use ImplicitPlot or simply use the graphics primitive Circle.
>
> >E.g {(x,y) | 0 => x,y =>1}? Like all points in 2D space that satisfies
> >this equation?
>
> Equation? This looks like an inequality which would be satisfied by all of
the points in the uppper left quadrant except for the strip 0 <= y < 1.
> --
> To reply via email subtract one hundred and four
>
--
Hi Bill.
Ofcourse it is x^2 + y^2 =1, my mistake.
Thanks you all for replies.
Regards,
Ronny Mandal
Prev by Date:
**Re: Wrong Limit**
Next by Date:
**Re: programatically feed Mathematica kernel location to MathKernel.Connect Method ?**
Previous by thread:
**Re: Parametric Plot**
Next by thread:
**kriging/spatial correlation**
| |