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Re: Integrate UnitStep, Bug?


On 8/27/04 at 2:57 AM, drbob at bigfoot.com (DrBob) wrote:

>I think both results are wrong, and the correct answer is Abs[b-a].
>Unless these Plots are wrong?

>b = 2; a = 3;
>Plot[fl[e](fr[e - a] - fr[e]), {e, -5, 5}, PlotStyle -> {Thickness[0.01]}]

This plot shows the function to be 0 for e < 0 or e > 2 and 1 otherwise. So, the integral is clearly 2 x 1 = 2 = Min[a,b] not Abs[b-a]

>b = 5; a = 3;
>Plot[fl[e](fr[e - a] - fr[e]), {e, -5, 5}, PlotStyle -> {Thickness[0.01]}]

This plot shows the function to be 0 for e < 0 or e > 3 and 1 otherwise. So, the integral is clearly 3 x 1 = 3 which again is Min[b,a]
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