Re: Re: Finding the Fourier transform of discrete functions

*To*: mathgroup at smc.vnet.net*Subject*: [mg52568] Re: [mg52524] Re: Finding the Fourier transform of discrete functions*From*: DrBob <drbob at bigfoot.com>*Date*: Thu, 2 Dec 2004 02:21:26 -0500 (EST)*References*: <cohi1d$1fh$1@smc.vnet.net> <200412011057.FAA19902@smc.vnet.net>*Reply-to*: drbob at bigfoot.com*Sender*: owner-wri-mathgroup at wolfram.com

>> what is a "discrete function". >> if it is a function, the parameter is continuous and FourierTransform[] >> compute the transformation. A discrete function is a function with a discrete domain. For instance, this is a discrete function on the obvious domain: f[x_Integer]/;1<=x<=12 = Sin@x It is NOT the Sin function, for the simple reason that the domain of a function (in math or mathematica) is part of its definition. Bobby On Wed, 1 Dec 2004 05:57:38 -0500 (EST), Jens-Peer Kuska <kuska at informatik.uni-leipzig.de> wrote: > Hi, > > what is a "discrete function". If it is discrete you have a array of > discrete data and Fourier[] compute the DFT of the array, if it is > a function, the parameter is continuous and FourierTransform[] > compute the transformation. > > Regards > Jens > > > "Luca" <luca at nospam.it> schrieb im Newsbeitrag > news:cohi1d$1fh$1 at smc.vnet.net... >> I found out it's possible to determine the Fourier transform of a >> function. I tried to look for the discrete fourier transform in the >> guide, but I can find the item in the list without any explaination of >> the function. Is it possible to find the Fourier transform of a >> discrete function? >> Thanks to everyone. >> >> Luca >> > > > > > -- DrBob at bigfoot.com www.eclecticdreams.net

**References**:**Re: Finding the Fourier transform of discrete functions***From:*"Jens-Peer Kuska" <kuska@informatik.uni-leipzig.de>