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MathGroup Archive 2004

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Re: Re: Finding the Fourier transform of discrete functions

  • To: mathgroup at smc.vnet.net
  • Subject: [mg52568] Re: [mg52524] Re: Finding the Fourier transform of discrete functions
  • From: DrBob <drbob at bigfoot.com>
  • Date: Thu, 2 Dec 2004 02:21:26 -0500 (EST)
  • References: <cohi1d$1fh$1@smc.vnet.net> <200412011057.FAA19902@smc.vnet.net>
  • Reply-to: drbob at bigfoot.com
  • Sender: owner-wri-mathgroup at wolfram.com

>> what is a "discrete function".
>> if it is a function, the parameter is continuous and FourierTransform[]
>> compute the transformation.

A discrete function is a function with a discrete domain.

For instance, this is a discrete function on the obvious domain:

f[x_Integer]/;1<=x<=12 = Sin@x

It is NOT the Sin function, for the simple reason that the domain of a function (in math or mathematica) is part of its definition.

Bobby

On Wed, 1 Dec 2004 05:57:38 -0500 (EST), Jens-Peer Kuska <kuska at informatik.uni-leipzig.de> wrote:

> Hi,
>
> what is a "discrete function". If it is discrete you have a array of
> discrete data and Fourier[] compute the DFT of the array, if it is
> a function, the parameter is continuous and FourierTransform[]
> compute the transformation.
>
> Regards
>   Jens
>
>
> "Luca" <luca at nospam.it> schrieb im Newsbeitrag
> news:cohi1d$1fh$1 at smc.vnet.net...
>> I found out it's possible to determine the Fourier transform of a
>> function. I tried to look for the discrete fourier transform in the
>> guide, but I can find the item in the list without any explaination of
>> the function. Is it possible to find the Fourier transform of a
>> discrete function?
>> Thanks to everyone.
>>
>> Luca
>>
>
>
>
>
>



-- 
DrBob at bigfoot.com
www.eclecticdreams.net


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