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Re: Re: Finding the Fourier transform of discrete functions

  • To: mathgroup at smc.vnet.net
  • Subject: [mg52582] Re: Re: Finding the Fourier transform of discrete functions
  • From: "Jens-Peer Kuska" <kuska at informatik.uni-leipzig.de>
  • Date: Fri, 3 Dec 2004 03:53:37 -0500 (EST)
  • Organization: Uni Leipzig
  • References: <cohi1d$1fh$1@smc.vnet.net> <200412011057.FAA19902@smc.vnet.net> <comgk7$7a2$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

and you think that 1<=x<12 is discret, and not a infinite number
of continuous values ?? Strange !

Regards
  Jens

"DrBob" <drbob at bigfoot.com> schrieb im Newsbeitrag 
news:comgk7$7a2$1 at smc.vnet.net...
>>> what is a "discrete function".
>>> if it is a function, the parameter is continuous and FourierTransform[]
>>> compute the transformation.
>
> A discrete function is a function with a discrete domain.
>
> For instance, this is a discrete function on the obvious domain:
>
> f[x_Integer]/;1<=x<=12 = Sin@x
>
> It is NOT the Sin function, for the simple reason that the domain of a 
> function (in math or mathematica) is part of its definition.
>
> Bobby
>
> On Wed, 1 Dec 2004 05:57:38 -0500 (EST), Jens-Peer Kuska 
> <kuska at informatik.uni-leipzig.de> wrote:
>
>> Hi,
>>
>> what is a "discrete function". If it is discrete you have a array of
>> discrete data and Fourier[] compute the DFT of the array, if it is
>> a function, the parameter is continuous and FourierTransform[]
>> compute the transformation.
>>
>> Regards
>>   Jens
>>
>>
>> "Luca" <luca at nospam.it> schrieb im Newsbeitrag
>> news:cohi1d$1fh$1 at smc.vnet.net...
>>> I found out it's possible to determine the Fourier transform of a
>>> function. I tried to look for the discrete fourier transform in the
>>> guide, but I can find the item in the list without any explaination of
>>> the function. Is it possible to find the Fourier transform of a
>>> discrete function?
>>> Thanks to everyone.
>>>
>>> Luca
>>>
>>
>>
>>
>>
>>
>
>
>
> -- 
> DrBob at bigfoot.com
> www.eclecticdreams.net
> 



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