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Re: How to evaluate Exp[I Pi(1+x)]?


E^(I*Pi*(1 + x))// ExpandAll // ComplexExpand // TrigToExp
-E^(I*Pi*x)

Maybe someone will give a shorter method.

David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/ 


From: hello [mailto:hello at noreply.com]
To: mathgroup at smc.vnet.net

Is there a way to evaluate Exp[I Pi (1+x)]? I am expecting to see the
result to be:

-Exp[I Pi x]

because Exp[I Pi] can be reduced to shorter form.





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