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Re: How to evaluate Exp[I Pi(1+x)]?
E^(I*Pi*(1 + x))// ExpandAll // ComplexExpand // TrigToExp -E^(I*Pi*x) Maybe someone will give a shorter method. David Park djmp at earthlink.net http://home.earthlink.net/~djmp/ From: hello [mailto:hello at noreply.com] To: mathgroup at smc.vnet.net Is there a way to evaluate Exp[I Pi (1+x)]? I am expecting to see the result to be: -Exp[I Pi x] because Exp[I Pi] can be reduced to shorter form.