Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2004
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2004

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: How to evaluate Exp[I Pi(1+x)]?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg52750] Re: How to evaluate Exp[I Pi(1+x)]?
  • From: nospam nospam <nospam_please at nospam.com>
  • Date: Sat, 11 Dec 2004 05:22:40 -0500 (EST)
  • References: <cpavhd$ivc$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

hello wrote:
> Is there a way to evaluate Exp[I Pi (1+x)]? I am expecting to see the
> result to be:
> 
> -Exp[I Pi x]
> 
> because Exp[I Pi] can be reduced to shorter form.
> 

ComplexExpand[Exp[I Pi (1 + x)]]

Cos[Pi (1 + x)] + I Sin[Pi (1 + x)]

(this is Euler formula)


  • Prev by Date: Re: How to evaluate Exp[I Pi(1+x)]?
  • Next by Date: Solve question
  • Previous by thread: Re: How to evaluate Exp[I Pi(1+x)]?
  • Next by thread: Re: How to evaluate Exp[I Pi(1+x)]?