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Re: How to evaluate Exp[I Pi(1+x)]?


hello wrote:
> Is there a way to evaluate Exp[I Pi (1+x)]? I am expecting to see the
> result to be:
> 
> -Exp[I Pi x]
> 
> because Exp[I Pi] can be reduced to shorter form.
> 

ComplexExpand[Exp[I Pi (1 + x)]]

Cos[Pi (1 + x)] + I Sin[Pi (1 + x)]

(this is Euler formula)


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