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MathGroup Archive 2004

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fullsimplify problem

  • To: mathgroup at smc.vnet.net
  • Subject: [mg52908] fullsimplify problem
  • From: "symbio" <symbio at has.com>
  • Date: Thu, 16 Dec 2004 03:41:11 -0500 (EST)
  • Reply-to: "symbio" <symbio at sha.com>
  • Sender: owner-wri-mathgroup at wolfram.com

Given ( - a / b^2) = =  ( + a / b^2), it can be written as (-2 a / b^2), but 
when I use FullSimplify on that equation, I get the incorrect result ( a / 
b ) = = 0.  How is this possible?

In[2]:=
-a/b^2 == a/b^2
% // FullSimplify
Out[2]=
\!\(\(-\(a\/b\^2\)\) == a\/b\^2\)
Out[3]=
\!\(a\/b == 0\)

In[5]:=
-2a/b^2 == 0 // FullSimplify
Out[5]=
\!\(a\/b == 0\)


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