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Re: fullsimplify problem


On 12/16/04 at 3:41 AM, symbio at has.com (symbio) wrote:

>Given ( - a / b^2) = =  ( + a / b^2), it can be written as (-2 a /
>b^2), 

Huh??? What is it you think can be written as (-2 a / b^2)?

subtracting (+a/b^2) from both sides gives

(-2 a/b^2) == 0

which clearly reduces to a/b == 0

>but when I use FullSimplify on that equation, I get the
>incorrect result ( a / b ) = = 0.  

Why do you think this is incorrect? What are you expecting?

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