Re: Re: Condition , FullSimplify

*To*: mathgroup at smc.vnet.net*Subject*: [mg53192] Re: [mg53184] Re: [mg53168] Condition , FullSimplify*From*: Andrzej Kozlowski <akoz at mimuw.edu.pl>*Date*: Tue, 28 Dec 2004 23:12:09 -0500 (EST)*References*: <200412271141.GAA12656@smc.vnet.net> <200412281130.GAA26991@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

I agree, except for the last sentence. Actually, expr/;condition can be used wherever patterns can be used. For example: Simplify[{Im[x],Im[y]},Element[x_/;x=!=y,Reals]] {0,Im[y]} Andrzej Kozlowski On 28 Dec 2004, at 20:30, DrBob wrote: >>> I find it useful and practical using the first notation. > > I don't see how, since it doesn't work! (You wouldn't be asking the > question, if it did.) > > The problem is that expr/;condition//FullSimplify doesn't mean > FullSimplify[expr,cond] in Mathematica; it's really just that simple. > > It does mean FullSimplify[expr/;condition], but that's not likely to > be of much use. As far as I can tell, expr/;condition is useless > without SetDelayed or RuleDelayed. > > Bobby > > On Mon, 27 Dec 2004 06:41:40 -0500 (EST), sebastian.cohen at gmail.com > <sebastian.cohen at gmail.com> wrote: > >> Wolfram Staff, >> >> I would like to know why the following class of statements don't work >> given >> >> expr /; condition // FullSimplify >> >> Although one may express them easily as >> >> FullSimplify[expr,cond] >> >> I find it useful and practical using the first notation. >> >> Is there a way to tell Mathematica at the end expressions both the >> conditions and to fullsimplify without having to write the whole >> fullsimplify function? >> >> Thanks in advance, >> >> Sebastian Cohen S >> >> >> >> > > > > -- > DrBob at bigfoot.com > www.eclecticdreams.net >

**References**:**Condition , FullSimplify***From:*"sebastian.cohen@gmail.com" <sebastian.cohen@gmail.com>

**Re: Condition , FullSimplify***From:*DrBob <drbob@bigfoot.com>