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Re: Condition , FullSimplify


>> I find it useful and practical using the first notation.

I don't see how, since it doesn't work! (You wouldn't be asking the question, if it did.)

The problem is that expr/;condition//FullSimplify doesn't mean FullSimplify[expr,cond] in Mathematica; it's really just that simple.

It does mean FullSimplify[expr/;condition], but that's not likely to be of much use. As far as I can tell, expr/;condition is useless without SetDelayed or RuleDelayed.

Bobby

On Mon, 27 Dec 2004 06:41:40 -0500 (EST), sebastian.cohen at gmail.com <sebastian.cohen at gmail.com> wrote:

> Wolfram Staff,
>
> I would like to know why the following class of statements don't work
> given
>
> expr /; condition // FullSimplify
>
> Although one may express them easily as
>
> FullSimplify[expr,cond]
>
> I find it useful and practical using the first notation.
>
> Is there a way to tell Mathematica at the end expressions both the
> conditions and to fullsimplify without having to write the whole
> fullsimplify function?
>
> Thanks in advance,
>
> Sebastian Cohen S
>
>
>
>



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