Re: Condition , FullSimplify
- To: mathgroup at smc.vnet.net
- Subject: [mg53184] Re: [mg53168] Condition , FullSimplify
- From: DrBob <drbob at bigfoot.com>
- Date: Tue, 28 Dec 2004 06:30:31 -0500 (EST)
- References: <200412271141.GAA12656@smc.vnet.net>
- Reply-to: drbob at bigfoot.com
- Sender: owner-wri-mathgroup at wolfram.com
>> I find it useful and practical using the first notation. I don't see how, since it doesn't work! (You wouldn't be asking the question, if it did.) The problem is that expr/;condition//FullSimplify doesn't mean FullSimplify[expr,cond] in Mathematica; it's really just that simple. It does mean FullSimplify[expr/;condition], but that's not likely to be of much use. As far as I can tell, expr/;condition is useless without SetDelayed or RuleDelayed. Bobby On Mon, 27 Dec 2004 06:41:40 -0500 (EST), sebastian.cohen at gmail.com <sebastian.cohen at gmail.com> wrote: > Wolfram Staff, > > I would like to know why the following class of statements don't work > given > > expr /; condition // FullSimplify > > Although one may express them easily as > > FullSimplify[expr,cond] > > I find it useful and practical using the first notation. > > Is there a way to tell Mathematica at the end expressions both the > conditions and to fullsimplify without having to write the whole > fullsimplify function? > > Thanks in advance, > > Sebastian Cohen S > > > > -- DrBob at bigfoot.com www.eclecticdreams.net
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