Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2004
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2004

[Date Index] [Thread Index] [Author Index]

Search the Archive

RE: derivation of a picewise defined function

  • To: mathgroup at smc.vnet.net
  • Subject: [mg46112] RE: [mg46098] derivation of a picewise defined function
  • From: "Florian Jaccard" <florian.jaccard at eiaj.ch>
  • Date: Sat, 7 Feb 2004 04:01:55 -0500 (EST)
  • Reply-to: <florian.jaccard at eiaj.ch>
  • Sender: owner-wri-mathgroup at wolfram.com

Use UnitStep :

h[x_] := UnitStep[x - 1]*x + UnitStep[-(x - 1)]E^(x - 1)

h[x] can be derivated, integrated, ploted, etc.
It's a good way to define picewise functions.

Meilleures salutations

Florian Jaccard


-----Message d'origine-----
De : M.L. Bondar [mailto:mbondar at win.tue.nl]
Envoyé : ven., 6. février 2004 10:15
À : mathgroup at smc.vnet.net
Objet : [mg46098] derivation of a picewise defined function


Hi,

I have the following problem. I need to work with the first derivative
of a picewise defined function.

A simple example :

h[x_] := x /; 1 <= x
h[x_] := E^(x - 1) /; x <= 1

I define
j[x_] := h'[x]

For 1<= x j[x] computes the values, j[x]=1 for all 1<=x, but for
x<=1 it returnes me j[x]=h'[x].

I need also the values of j for x<=1. How can I do that with
Mathematica?

Thank you.

Luiza


  • Prev by Date: Re: time serie -> sum inside a loop
  • Next by Date: Re: derivation of a picewise defined function
  • Previous by thread: Re: derivation of a picewise defined function
  • Next by thread: Re: derivation of a picewise defined function