       Re: derivation of a picewise defined function

• To: mathgroup at smc.vnet.net
• Subject: [mg46124] Re: derivation of a picewise defined function
• From: "David W. Cantrell" <DWCantrell at sigmaxi.org>
• Date: Sat, 7 Feb 2004 04:02:05 -0500 (EST)
• References: <bvvnam\$j4h\$1@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```"M.L. Bondar" <mbondar at win.tue.nl> wrote:
> I have the following problem. I need to work with the first derivative
> of a picewise defined function.
>
> A simple example :
>
> h[x_] := x /; 1 <= x
> h[x_] := E^(x - 1) /; x <= 1
>
> I define
> j[x_] := h'[x]
>
> For 1<= x j[x] computes the values, j[x]=1 for all 1<=x, but for
> x<=1 it returnes me j[x]=h'[x].
>
> I need also the values of j for x<=1. How can I do that with
> Mathematica?

I suggest that you rewrite your function using UnitStep as

In:= h[x_] := E^(x - 1) + UnitStep[x - 1](x - E^(x - 1))

Then differentiating and simplifying gives what I think you want

In:= D[h[x], x]

Out= E^(-1 + x) + (-E^(-1 + x) + x)*DiracDelta[-1 + x] +
(1 - E^(-1 + x))*UnitStep[-1 + x]

In:= Simplify[%]

Out= E^(-1 + x) + (1 - E^(-1 + x))*UnitStep[-1 + x]

David

```

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