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MathGroup Archive 2004

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Re: 3D Pascal's Triangle (Cone?)

  • To: mathgroup at
  • Subject: [mg49575] Re: 3D Pascal's Triangle (Cone?)
  • From: "Roger L. Bagula" <rlbtftn at>
  • Date: Fri, 23 Jul 2004 06:01:47 -0400 (EDT)
  • References: <> <cdnq13$l3v$>
  • Reply-to: tftn at
  • Sender: owner-wri-mathgroup at

typo: extra "}" in the cuboid:

Roger L. Bagula wrote:
> There is and old Visualization in Mathematica that
> gives a modulo 2 version of a Pascal's triangle.
> It is a right angle version of a tetrahedral 3d Sierpiski triangle.
> Here it is: ( copyright Mathematica):
> g=Flatten[Table[If 
> Mod[Multinomial[x,y,x],2]==1,Cuboid[1.2*{x,y,-z}}],{}],{x,0,15},{y.0,15},{z,0,15}]
> Show[Graphics3D[g]]
> phil wrote:
>>Is there a three dimensional version of Pascal's
>>triangle? If so, I suppose it would be a cone (?).

Respectfully, Roger L. Bagula
tftn at, 11759Waterhill Road, Lakeside,Ca 92040-2905,tel: 
619-5610814 :

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