Re: Re: 3D Pascal's Triangle (Cone?)
- To: mathgroup at smc.vnet.net
- Subject: [mg49604] Re: [mg49575] Re: 3D Pascal's Triangle (Cone?)
- From: DrBob <drbob at bigfoot.com>
- Date: Sat, 24 Jul 2004 03:47:46 -0400 (EDT)
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- Reply-to: drbob at bigfoot.com
- Sender: owner-wri-mathgroup at wolfram.com
Alas, no, it isn't attached. It's embedded as 300K of text, and I won't spend 5 to 10 minutes copying and pasting it. It really takes that long to hold down the mouse and scroll, and I'm really not switching to another e-mail program. (I don't know if that would help, and anyway, I'm not doing it.) A couple of suggestions to avoid wasting everybody's time: If you copy and paste the code, you can avoid the typos. Omega Consulting's "Copy as InputForm" palette is often useful for that (unless it's incompatible with your Mathematica version?). Without it, special symbols cause the pasted code to be unreadable to humans. http://eclecticdreams.net/DrBob/copy_as_inputform.htm Or, after you've written the code in e-mail, you could copy and paste it BACK into Mathematica, and execute it to see if you missed anything. It only takes a few seconds. Bobby On Fri, 23 Jul 2004 11:25:29 -0700, Roger Bagula <tftn at earthlink.net> wrote: > The complete notebook is attached. > > DrBob wrote: > >> That was one typo down, and three to go (missing "[", missing "]", and >> "." where you should have ","). >> >> It should be: >> >> g = Flatten[Table[If[Mod[Multinomial[x, y, >> x], 2] == 1, Cuboid[1.2*{x, y, -z}], {}], {x, 0, 15}, {y, 0, >> 15}, {z, >> 0, 15}]] >> Show[Graphics3D[g]] >> >> But the resulting plot is just a rectangular brick wall, not a >> triangle of any kind. >> >> Bobby >> >> On Fri, 23 Jul 2004 06:01:47 -0400 (EDT), Roger L. Bagula >> <rlbtftn at netscape.net> wrote: >> >>> typo: extra "}" in the cuboid: >>> g=Flatten[Table[If >>> Mod[Multinomial[x,y,x],2]==1,Cuboid[1.2*{x,y,-z}],{}],{x,0,15},{y.0,15},{z,0,15}] >>> Show[Graphics3D[g]] >>> >>> Roger L. Bagula wrote: >>> >>>> There is and old Visualization in Mathematica that >>>> gives a modulo 2 version of a Pascal's triangle. >>>> It is a right angle version of a tetrahedral 3d Sierpiski triangle. >>>> Here it is: ( copyright Mathematica): >>>> >>>> g=Flatten[Table[If >>>> Mod[Multinomial[x,y,x],2]==1,Cuboid[1.2*{x,y,-z}}],{}],{x,0,15},{y.0,15},{z,0,15}] >>>> Show[Graphics3D[g]] >>>> >>>> phil wrote: >>>> >>>>> Is there a three dimensional version of Pascal's >>>>> triangle? If so, I suppose it would be a cone (?). >>>>> Applications? >>>>> >>>>> phil >>>>> >>>> >>>> >>>> >>> >>> >> >> >> > -- DrBob at bigfoot.com www.eclecticdreams.net
- References:
- Re: 3D Pascal's Triangle (Cone?)
- From: "Roger L. Bagula" <rlbtftn@netscape.net>
- Re: 3D Pascal's Triangle (Cone?)