Re: PlotPoints in plot

• To: mathgroup at smc.vnet.net
• Subject: [mg48647] Re: PlotPoints in plot
• From: V.Cejka at seznam.cz (Vasek)
• Date: Wed, 9 Jun 2004 04:17:11 -0400 (EDT)
• References: <16ykpxjjusq0@legacy>
• Sender: owner-wri-mathgroup at wolfram.com

```In 2D Plot PlotPoints option gives starting number of points in the
plot, but if mathematica sees it is not enough for good evaluation, it
Try Plot[Print[x]; Sqrt[1 - x^2], {x, -1, 1}, PlotPoints -> 3] to see
all evaluations.
You can use PlotDivision option to set max. number of subdivisions
between initial points, but value 0 is not valid and it won´t help you
in this case.

Probably the easiest solution is to generate partially linear function
(like Plot[(-x + 17/2)UnitStep[x - 5] + (x - 3/2)(1 - UnitStep[x -
5]), {x, 0, 10}])
or use Show[Graphics[{Line[{{0, 0}, {1, 1}, {2, 0}}]}], Axes -> True]
command.

On 2 Jun 04 10:51:44 -0400 (EDT), G.L.Narasimham wrote:
>For the plot command  Plot[Sqrt[1-x^2],{x,-1,1},PlotPoints->3]
>I expected to see a triangle joining 3 points on a circle, but a
>continuous line ( default PlotPoints->20? )appears. However,
>ParametricPlot3D[{Cos[t],Sin[t],0},{t,0,Pi},PlotPoints->3,ViewPoint->{0,0,5}]
>gives a triangle. How to get a polygon of straight sides in the
>unparametered Plot?

```

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