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Re: seruous solve bug? only when used with simplifying
*To*: mathgroup at smc.vnet.net
*Subject*: [mg48690] Re: seruous solve bug? only when used with simplifying
*From*: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
*Date*: Thu, 10 Jun 2004 02:44:23 -0400 (EDT)
*Organization*: Universitaet Leipzig
*References*: <ca6haa$fef$1@smc.vnet.net>
*Reply-to*: kuska at informatik.uni-leipzig.de
*Sender*: owner-wri-mathgroup at wolfram.com
Hi,
ohhh the situation is even mutch wronger than you think,
you don't need to use Simplify[] and FullSimplify[] to
find the bug just try
and get False, the situation is just the same
with
TrueQ[a^2+2*a*b+b^2==(a+b)^2]
and if you would like to read the manual what TrueQ[]
does and what Equal[] mean than it would be clear that
you have not found a bug.
And yes Simplify[] and FullSimplify[] change the
system so much that they are not Equal[] but the
system is still equal, because the Mathematica function
Equal[] has a different meaning than "equal".
Then only solution to the problem above is to use
TrueQ[2*a + 2*b == 2(a + b) // FullSimplify]
TrueQ[a^2 + 2*a*b + b^2 == (a + b)^2 // FullSimplify]
but you can't use it, because you just found out that
it has "serious ... bug" too bad.
Regards
Jens
sean kim wrote:
>
> hello group,
>
> i think i have a serious Solve[], Simplify[], FullSimplify[] bug...
>
> Take a system of equations as below. (apb is actually (a+b). i defined
> it as apb to keep Mathematica crunching away at it)
>
> sys =
> {c1[t] == (c*(16*a^4 + 8*a^3*kd + 4*a^2*apb*kd + 2*a*apb^2*kd +
> apb^3*kd))/(apb^4*kd),
> c2[t] == (2*(8*a^3 + 4*a^2*apb + 2*a*apb^2 + apb^3)*b*c)/(apb^4*d),
> c3[t] == (2*(8*a^3 + 4*a^2*apb + 2*a*apb^2 + apb^3)*b*c)/(apb^4*kd)}
>
> sys1 = sys /.{apb -> (a + b)}
> sys2 = sys/.{apb -> (a + b)}//Simplify
> sys3 = sys/.{apb -> (a + b)}//FullSimplify
>
> and then use
>
> TrueQ[sys1 == sys1]
> TrueQ[sys1 == sys2]
> TrueQ[sys1 == sys3]
> TrueQ[sys2 == sys3]
>
> then it gives,
>
> Out[18]=True
> Out[19]=False
> Out[20]=False
> Out[21]=False
>
> Simplify and FullSimplify changed the system so much that they are not
> equal?
>
> Basically, unless I define the (a+b) as a single constant apb, the Mathematica
> will do soemthing with it then it messes it up. I think...
>
> Why is this happening? and how do i prevent it from happening again
> with other more obsucre systems? Above I got lucky in finding the
> cause (a+b)
>
> thanks in advance for any and all comments.
>
> Sean
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