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MathGroup Archive 2004

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Re: How to modify Convex Hull program to give output as Cartesian Coordinates?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg48767] Re: How to modify Convex Hull program to give output as Cartesian Coordinates?
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Wed, 16 Jun 2004 04:54:07 -0400 (EDT)
  • Organization: Universitaet Leipzig
  • References: <cam6fd$qjj$1@smc.vnet.net>
  • Reply-to: kuska at informatik.uni-leipzig.de
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

with you input below

data2D[[#]] & /@ convexhull

should do that.

Regards
  Jens


Gilmar Rodr?guez Pierluissi wrote:
> 
> Greetings Mathematica Group!:
> 
> I use the following example, to formulate my question:
> 
> In[1]: data2D = {{4.4, 14}, {6.7, 15.25}, {6.9, 12.8}, {2.1, 11.1},
>                 {9.5, 14.9},{13.2, 11.9}, {10.3, 12.3}, {6.8, 9.5},
>                 {3.3, 7.7}, {0.6, 5.1},{5.3, 2.4},{8.45, 4.7},
>                 {11.5, 9.6},{13.8, 7.3}, {12.9, 3.1}, {11, 1.1}};
> 
> In[2]: << DiscreteMath`ComputationalGeometry`
> 
> In[3]: convexhull = ConvexHull[data2D]
> 
> Out[3]: {14,6,5,2,1,4,10,11,16,15}
> 
> My question is:
> 
> Is there any way to modify the ConvexHull program to give the
> Cartesian coordinates of the points corresponding to the values
> 14,6,5,2,1,4,10,11,16,15; instead of Out[3] above?
> 
> Thank you!


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