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Re: How to calculate the derivative of matrix w.r.t another matrix?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg46715] Re: How to calculate the derivative of matrix w.r.t another matrix?
*From*: Paul Abbott <paul at physics.uwa.edu.au>
*Date*: Tue, 2 Mar 2004 19:10:13 -0500 (EST)
*Organization*: The University of Western Australia
*References*: <c215ts$8gh$1@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
In article <c215ts$8gh$1 at smc.vnet.net>, "Fred" <f0z6305 at labs.tamu.edu>
wrote:
> I have a problem of calculating the derivative of dxm matrix A with respect
> to another dxm matrix B,
> where A= [a1 a2 ... am] and B =[b1 b2 ... bm] with
> ai and bj are vectors.
one matrix with respect to another! That would mean something else
altogether. It looks like you are after an element by element operation.
> Actually the matrix A itself is the first order derivative
> of a scalar J with respect to B, i.e., A = dJ/dB,
> where a1 = dJ/db1, a2 = dJ/db1, and so on.
This is an extension of the gradient operator. For example, for
specified b, say
b = {{x, y}, {z, t}};
and j, say
j = x^2 + y^2 + z^2 - c t^2;
you can compute dj/db using Outer:
a = First[Outer[D, {j}, b]]
> Now dA/dB is the second order derivative
> dA/dB = dJ^2/(dBdB')
> = [dJ/db1 dJ/db1 ... dJ/dbm]/d[b1 b2 ... bm].
>
> So anybody have some idea on how to derive the formulation of dA/dB?
Again, this is just an Outer product:
Outer[D, a, b]
Cheers,
Paul
--
Paul Abbott Phone: +61 8 9380 2734
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