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MathGroup Archive 2004

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Re: Expansion of an exponential expression

  • To: mathgroup at smc.vnet.net
  • Subject: [mg47214] Re: Expansion of an exponential expression
  • From: bobhanlon at aol.com (Bob Hanlon)
  • Date: Wed, 31 Mar 2004 02:57:34 -0500 (EST)
  • References: <c4bdrj$6uu$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

anlog=Log[((2+Sqrt[1+2*h])^(-1))^(t/h)];

PowerExpand[anlog]

Simplify[anlog, Element[t, Reals]&&h>0]

Simplify[anlog, h>0&&t>0]


Bob Hanlon

In article <c4bdrj$6uu$1 at smc.vnet.net>, carlos at colorado.edu (Carlos Felippa)
wrote:

<< As a result of some calculations I have
(a snipet of a more complex expression)

anlog= Log[ ((2 + Sqrt[1 + 2*h])^(-1))^(t/h)   ]

I would like to simplify this to 

anlog= (t/h) Log[((2 + Sqrt[1 + 2*h])^(-1))   ]

so I can then take the Taylor series in h.
But FullSimplify[anlog,h>0]  doesnt do it.
Do i need a ComplexityFunction?


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