Re: Expansion of an exponential expression

*To*: mathgroup at smc.vnet.net*Subject*: [mg47232] Re: Expansion of an exponential expression*From*: "Steve Luttrell" <steve1 at _removemefirst_luttrell.org.uk>*Date*: Wed, 31 Mar 2004 02:59:09 -0500 (EST)*References*: <c4bdrj$6uu$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

If you evaluate PowerExpand[anlog] you get -((t*Log[2 + Sqrt[1 + 2*h]])/h) which is similar to (preferable to, IMHO) what you want. Steve Luttrell "Carlos Felippa" <carlos at colorado.edu> wrote in message news:c4bdrj$6uu$1 at smc.vnet.net... > As a result of some calculations I have > (a snipet of a more complex expression) > > anlog= Log[ ((2 + Sqrt[1 + 2*h])^(-1))^(t/h) ] > > I would like to simplify this to > > anlog= (t/h) Log[((2 + Sqrt[1 + 2*h])^(-1)) ] > > so I can then take the Taylor series in h. > But FullSimplify[anlog,h>0] doesnt do it. > Do i need a ComplexityFunction? >