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Re: Expansion of an exponential expression


If you evaluate
PowerExpand[anlog]

you get

-((t*Log[2 + Sqrt[1 + 2*h]])/h)

which is similar to (preferable to, IMHO) what you want.

Steve Luttrell

"Carlos Felippa" <carlos at colorado.edu> wrote in message
news:c4bdrj$6uu$1 at smc.vnet.net...
> As a result of some calculations I have
> (a snipet of a more complex expression)
>
> anlog= Log[ ((2 + Sqrt[1 + 2*h])^(-1))^(t/h)   ]
>
> I would like to simplify this to
>
> anlog= (t/h) Log[((2 + Sqrt[1 + 2*h])^(-1))   ]
>
> so I can then take the Taylor series in h.
> But FullSimplify[anlog,h>0]  doesnt do it.
> Do i need a ComplexityFunction?
>


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