Re: Expansion of an exponential expression

*To*: mathgroup at smc.vnet.net*Subject*: [mg47243] Re: Expansion of an exponential expression*From*: Bill Rowe <readnewsciv at earthlink.net>*Date*: Wed, 31 Mar 2004 02:59:49 -0500 (EST)*Sender*: owner-wri-mathgroup at wolfram.com

On 3/30/04 at 4:02 AM, carlos at colorado.edu (Carlos Felippa) wrote: >As a result of some calculations I have (a snipet of a more complex >expression) >anlog= Log[ ((2 + Sqrt[1 + 2*h])^(-1))^(t/h) ] >I would like to simplify this to >anlog= (t/h) Log[((2 + Sqrt[1 + 2*h])^(-1)) ] try PowerExpand as in In[1]:= PowerExpand[ Log[((2 + Sqrt[1 + 2*h])^(-1))^(t/h)]] Out[1]= -((t*Log[Sqrt[2*h + 1] + 2])/h) but you should be aware the transformations made by PowerExpand will not always produce what you expect. For example PowerExpand[(a b)^c] yeilds a^c b^c. If you set a = -4, b = -9 and c = 1/2, then Mathematica gives 6 for (a b)^c and -6 for a^c b^c -- To reply via email subtract one hundred and four