Re: Constant function Integrate Assumption

*To*: mathgroup at smc.vnet.net*Subject*: [mg47212] Re: Constant function Integrate Assumption*From*: bobhanlon at aol.com (Bob Hanlon)*Date*: Wed, 31 Mar 2004 02:57:31 -0500 (EST)*References*: <c4bdnf$6tr$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

With[{Months = 1}, Integrate[UnitStep[t Months], t]] Integrate[UnitStep[t Months], t, Assumptions -> Months == 1] Integrate[UnitStep[t Months] /. Months -> 1, t] Integrate[UnitStep[t Months] /. x_*Months -> x, t] Bob Hanlon In article <c4bdnf$6tr$1 at smc.vnet.net>, dsr14 at Cornell.edu (Daryl Reece) wrote: << I am trying to use units within an Integration and would like Mathematica to understand that the units (Month) are not a function of the integration variable, but I have not had any luck with my attempts. Specifically Integrate[UnitStep[t Months], t] should yield t UnitStep[t] but I get the unevaluated form, because Mathematica does not know how to assume that Month is not a function of t. I've tried Assumptions, SetAttribute, Replace...to no avail. I've also hunted extensively online (Wolfram, this group and MathGroup) without any results, so any help would be greatly appreciated.