MathGroup Archive 2004

[Date Index] [Thread Index] [Author Index]

Search the Archive

(a b)^n --> a^n*b^n via Refine


Hi Group,
could someone help me in grasping why this work:
Refine[(b^r)^p, Element[{r, p}, Integers]] --> b^(p*r)

and this not

Refine[(a*b)^p, Element[ p, Integers]] --> a^p*b^p

In the documentation of PowerExpand it is stated that (a*b)^n == a^n*b^n for
every integer n, as we can see by evaluating (x y)^Range[-3, 3]. ?!?!

Greetings from Croatia,
Drago Ganic



  • Prev by Date: How to get the real part of an integral?
  • Next by Date: complex analysis problem in mathematica 3.0
  • Previous by thread: How to get the real part of an integral?
  • Next by thread: complex analysis problem in mathematica 3.0