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MathGroup Archive 2004

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(a b)^n --> a^n*b^n via Refine

  • To: mathgroup at smc.vnet.net
  • Subject: [mg48455] (a b)^n --> a^n*b^n via Refine
  • From: "Drago Ganic" <drago.ganic at in2.hr>
  • Date: Mon, 31 May 2004 00:13:30 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

Hi Group,
could someone help me in grasping why this work:
Refine[(b^r)^p, Element[{r, p}, Integers]] --> b^(p*r)

and this not

Refine[(a*b)^p, Element[ p, Integers]] --> a^p*b^p

In the documentation of PowerExpand it is stated that (a*b)^n == a^n*b^n for
every integer n, as we can see by evaluating (x y)^Range[-3, 3]. ?!?!

Greetings from Croatia,
Drago Ganic



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