Re: plot variance(s)
- To: mathgroup at smc.vnet.net
- Subject: [mg51777] Re: [mg51749] plot variance(s)
- From: DrBob <drbob at bigfoot.com>
- Date: Mon, 1 Nov 2004 02:53:53 -0500 (EST)
- References: <200410310617.BAA16305@smc.vnet.net>
- Reply-to: drbob at bigfoot.com
- Sender: owner-wri-mathgroup at wolfram.com
>> Why doesn't p2 directly overlay the dots in p1? ListPlot assumes the x-coordinates (when you don't specify them) are 1, ..., Length@data. To get the right results, specify the x-coordinates: data = Table[{x, Sin[x]}, {x, 0, 2*Pi}]; p1 = ListPlot[data, PlotStyle -> {Red, PointSize[0.03]}, DisplayFunction -> Identity]; p2 = Plot[Sin[x], {x, 0, 2*Pi}, DisplayFunction -> Identity]; Show[p1, p2, DisplayFunction -> $DisplayFunction]; or data = Table[Sin[x], {x, 0, 2*Pi}]; p1 = ListPlot[Transpose[{Range[0, 2*Pi], data}], PlotStyle -> {Red, PointSize[0.03]}, DisplayFunction -> Identity]; p2 = Plot[Sin[x], {x, 0, 2*Pi}, DisplayFunction -> Identity]; Show[p1, p2, DisplayFunction -> $DisplayFunction]; or just DisplayTogether[Graphics[{PointSize[0.03], Red, Table[Point@{x, Sin[x]}, {x, 0, 2*Pi}]}], Plot[Sin[x], {x, 0, 2*Pi}]]; I don't think ListPlot is very useful, in general. Bobby On Sun, 31 Oct 2004 01:17:31 -0500 (EST), Steven Shippee <slshippee at comcast.net> wrote: > Input1: data = Table[Sin[x], {x, 0, 2\[Pi]}]; > > Input 2: p1 = ListPlot[data, > PlotStyle -> {Red, PointSize[0.03]}, DisplayFunction -> Identity]; > > Input 3: p2 = Plot[Sin[x], {x, 0, 2\[Pi]}, DisplayFunction -> Identity]; > > Input 4: Show[p1, p2, DisplayFunction -> $DisplayFunction]; > > Why doesn't p2 directly overlay the dots in p1? Thanks in advance, > > Steven Shippee > > slshippee at comcast.net > > 360-493-8353 > > > > > > -- DrBob at bigfoot.com www.eclecticdreams.net