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MathGroup Archive 2004

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Re: Re: Poles and Complex Factoring

  • To: mathgroup at smc.vnet.net
  • Subject: [mg52130] Re: [mg52097] Re: [mg6011] Poles and Complex Factoring
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Thu, 11 Nov 2004 04:53:14 -0500 (EST)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

Factor[x^2+2x+10, GaussianIntegers -> True]

(x + (1 - 3*I))*(x + (1 + 3*I))


Bob Hanlon

> 
> From: bokat02 at hotmail.com (bokat)
To: mathgroup at smc.vnet.net
> Date: 2004/11/10 Wed AM 04:46:08 EST
> To: mathgroup at smc.vnet.net
> Subject: [mg52130] [mg52097] Re: [mg6011] Poles and Complex Factoring
> 
> the complex factoring is wrong 
> 
> On 11 Feb 1997 01:29:40 -0500, peter wrote:
> >Dear All,
> >
> >I know how to calculate the residue of a fuction using Mathematica, but 
how
> can I 
> >use Mathematica to calculate the order of a complex pole? 
> >
> >It would also be nice for Mathematica to tell me if a particular singularity
> is an 
> >essential singularity, removable singularity or a pole...but this is
> not 
> >necessary; just icing on the cake.
> >
> >Also, is there a way to factor polynomials with imaginary roots?  
> >Something like: 
> >
> >    Factor[ x^2 + 2x + 10 ]  =  (x - 1 + 4.5 I)(x - 1 - 4.5 I)
> >
> >Much thanks in advance!
> >
> >Peter



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