Re: Re: Poles and Complex Factoring

*To*: mathgroup at smc.vnet.net*Subject*: [mg52130] Re: [mg52097] Re: [mg6011] Poles and Complex Factoring*From*: Bob Hanlon <hanlonr at cox.net>*Date*: Thu, 11 Nov 2004 04:53:14 -0500 (EST)*Reply-to*: hanlonr at cox.net*Sender*: owner-wri-mathgroup at wolfram.com

Factor[x^2+2x+10, GaussianIntegers -> True] (x + (1 - 3*I))*(x + (1 + 3*I)) Bob Hanlon > > From: bokat02 at hotmail.com (bokat) To: mathgroup at smc.vnet.net > Date: 2004/11/10 Wed AM 04:46:08 EST > To: mathgroup at smc.vnet.net > Subject: [mg52130] [mg52097] Re: [mg6011] Poles and Complex Factoring > > the complex factoring is wrong > > On 11 Feb 1997 01:29:40 -0500, peter wrote: > >Dear All, > > > >I know how to calculate the residue of a fuction using Mathematica, but how > can I > >use Mathematica to calculate the order of a complex pole? > > > >It would also be nice for Mathematica to tell me if a particular singularity > is an > >essential singularity, removable singularity or a pole...but this is > not > >necessary; just icing on the cake. > > > >Also, is there a way to factor polynomials with imaginary roots? > >Something like: > > > > Factor[ x^2 + 2x + 10 ] = (x - 1 + 4.5 I)(x - 1 - 4.5 I) > > > >Much thanks in advance! > > > >Peter