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Re: Re: Poles and Complex Factoring

• To: mathgroup at smc.vnet.net
• Subject: [mg52106] Re: [mg52097] Re: [mg6011] Poles and Complex Factoring
• From: yehuda ben-shimol <benshimo at bgu.ac.il>
• Date: Thu, 11 Nov 2004 04:52:07 -0500 (EST)
• References: <200411100946.EAA11299@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

Use the GaussianIntegers option
Factor[x^2 + 2x + 10, GaussianIntegers -> True]
and get
((1 - 3 \[ImaginaryI]) + x) ((1 + 3 \[ImaginaryI]) + x)
yehuda

bokat wrote:

>the complex factoring is wrong 
>
>On 11 Feb 1997 01:29:40 -0500, peter wrote:
>  
>
>>Dear All,
>>
>>I know how to calculate the residue of a fuction using Mathematica, but how
>>    
>>
>can I 
>  
>
>>use Mathematica to calculate the order of a complex pole? 
>>
>>It would also be nice for Mathematica to tell me if a particular singularity
>>    
>>
>is an 
>  
>
>>essential singularity, removable singularity or a pole...but this is
>>    
>>
>not 
>  
>
>>necessary; just icing on the cake.
>>
>>Also, is there a way to factor polynomials with imaginary roots?  
>>Something like: 
>>
>>   Factor[ x^2 + 2x + 10 ]  =  (x - 1 + 4.5 I)(x - 1 - 4.5 I)
>>
>>Much thanks in advance!
>>
>>Peter
>>
>>--
>>Birthdays are good for you:  A federal funded project has recently
>>    
>>
>determined
>  
>
>>that people with the most number of birthdays will live the
>>    
>>
>longest.....
>  
>

• References:
  • Re: Poles and Complex Factoring
    • From: bokat02@hotmail.com (bokat)