MathGroup Archive 2004

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UnitStep


Why does the following give me 'indeterminate, infinite expression
encountered', etc. instead of  zero....


(1/p) UnitStep[p-1] /.p->0


I defined a function using the UnitStep because p could  = 0  and I
thought this would be the way around that problem.......but didnt work
the way I expected.....


jerry blimbaum



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