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Re: On constants and D's behaviour


You need to use Dt rather than D.

Thus

Dt[a,x]

gives

Dt[a,x]

whereas

Dt[a,x,Constants\[Rule]{a}]

gives

0

Steve Luttrell

"Nicolas Girard" <nicolas.girard at strasbourg.fr> wrote in message 
news:co97pg$gub$1 at smc.vnet.net...
> Dear people,
> just a thought, from a frustrated mind:
>
> given that one can explicitely tell a symbol is a constant by modifying
> its attributes, then why the hell doesn't the partial derivative D take
> advantage of it, and treat nonconstant symbol as.... nonconstants, by
> default ??
>
> Cheers,
> Nicolas
> 



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