Re: sort procedure
- To: mathgroup at smc.vnet.net
- Subject: [mg52509] Re: sort procedure
- From: "Steve Luttrell" <steve_usenet at _removemefirst_luttrell.org.uk>
- Date: Tue, 30 Nov 2004 05:24:21 -0500 (EST)
- References: <coefho$rei$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
The Sort function with a user-defined sort function is the most flexible way of doing this sort of thing. Here is an example: Define a data set with 10 paired observations: s=Map[Reverse,Partition[Table[Random[],{10}],2,1]] {{0.12873,0.696262},{0.884034,0.12873},{0.576172,0.884034},{0.707075, 0.576172},{0.340009,0.707075},{0.687427,0.340009},{0.513483, 0.687427},{0.99377,0.513483},{0.78212,0.99377}} Sort it as specified: Sort[s, #2[[2]] > #1[[2]] & ] {{0.884034,0.12873},{0.687427,0.340009},{0.99377,0.513483},{0.707075, 0.576172},{0.513483,0.687427},{0.12873,0.696262},{0.340009, 0.707075},{0.576172,0.884034},{0.78212,0.99377}} Steve Luttrell "paolo " <tarpanelli at libero.it> wrote in message news:coefho$rei$1 at smc.vnet.net... > If I have a data serie of n paired observations (x_t,x_t-1) ordered > according to time, how can i re-order this serie according to the size of > x_t-1 > > The procedure Sort it seems it does not work well. > anyone has suggestions? > thanks > > P. > > > > ____________________________________________________________ > Libero ADSL: navighi gratis a 1.2 Mega, senza canone e costi di > attivazione. > Abbonati subito su http://www.libero.it > >