Re: sort procedure

*To*: mathgroup at smc.vnet.net*Subject*: [mg52500] Re: [mg52483] sort procedure*From*: yehuda ben-shimol <benshimo at bgu.ac.il>*Date*: Tue, 30 Nov 2004 05:24:02 -0500 (EST)*References*: <200411290622.BAA27959@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

First, the Sort[] function is very flexible, so actually you can use ANY sort criterion you like to sort. I'm not sure that I fully understand the arrangements of your measurements you have a list element of the form zi={{x0,x1,x2,...,xk},{y0,y1,y2,...,ym}} where the xi are taken at time t and the yi taken at time t-1, z={z0,z1,z2,...,zn} (n pairs). Then in this case use Sort[z,Length[#1[[2]]] <Length[#2[[2]]]&]. If the arrangement of your measurements is different than my understanding, please correct me. yehuda On Monday 29 November 2004 08:22, paolo wrote: > If I have a data serie of n paired observations (x_t,x_t-1) ordered > according to time, how can i re-order this serie according to the size of > x_t-1 > > The procedure Sort it seems it does not work well. > anyone has suggestions? > thanks > > P. > > > > ____________________________________________________________ > Libero ADSL: navighi gratis a 1.2 Mega, senza canone e costi di > attivazione. Abbonati subito su http://www.libero.it

**References**:**sort procedure***From:*"paolo " <tarpanelli@libero.it>