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MathGroup Archive 2004

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Re: Re: solve and simplify. force left hand side to be 0==

  • To: mathgroup at smc.vnet.net
  • Subject: [mg51196] Re: [mg51182] Re: [mg51152] solve and simplify. force left hand side to be 0==
  • From: Richard Palmer <mapsinc at bellatlantic.net>
  • Date: Fri, 8 Oct 2004 02:54:43 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

Thanks!  That was the clue I needed.

Richard

On 10/7/04 5:26 AM, "DrBob" <drbob at bigfoot.com> wrote:

> sde = {0 ==
>    v1 - d1 e[
>        0] + k2 es[0] - k1 e[0] s[0], 0 == -k2 es[0] - k3 es[
>          0] + k1 e[0] s[0], 0 == k3
>      es[0] - d3 p[0], 0 == v2 + k2 es[0] - d2 s[0] - k1 e[0] s[0]};
> sde1 = sde /. First@Solve[sde[[1]], e[0]];
> 0 == HoldForm[Evaluate@Simplify@Last@#] & /@ sde1
> 
> Bobby
> 
> On Wed, 6 Oct 2004 04:34:39 -0400 (EDT), sean kim <sean_incali at yahoo.com>
> wrote:
> 
>> 
>> consider a system such as,
>> 
>> sde = {
>> 0==v1-d1 e[0]+k2 es[0]-k1 e[0] s[0],
>> 0==-k2 es[0]-k3 es[0]+k1 e[0] s[0],
>> 0==k3 es[0]-d3 p[0],
>> 0==v2+k2 es[0]-d2 s[0]-k1 e[0] s[0]};
>> 
>> sv = {e[0],es[0],p[0],s[0]};
>> 
>> Solve[sde[[1]], e[0]]
>> 
>> sde1= sde/.%
>> 
>> %//Simplify
>> 
>> shows once I simplify the solution, the structure of
>> 0== stuff... is lost.
>> 
>> is there anyway to force Simplify to keep the
>> structure so that left hand side is always 0== stuff?
>> 
>> thanks in advance  for any insights.
>> 
>> 
>> sean
>> 
>> 
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>> 
>> 
> 
> 


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