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MathGroup Archive 2004

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Re: conditionnal rule

  • To: mathgroup at smc.vnet.net
  • Subject: [mg51521] Re: [mg51499] conditionnal rule
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Thu, 21 Oct 2004 22:20:29 -0400 (EDT)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

myList={{a,b},{c,d}};

myList/.{a_,x_?(!(Head[#]===List)&)}->{a,d}

{{a, d}, {c, d}}

myList/.{a_,x_?(Head[#]==Symbol&)}->{a,d}

{{a, d}, {c, d}}

myList/.{a_,x_?AtomQ}->{a,d}

{{a, d}, {c, d}}

myList/.{a_,x_?(Length[#]==0&)}->{a,d}

{{a, d}, {c, d}}


Bob Hanlon

> 
> From: darkness_wizard at hotmail.com (Wishmaster7)
To: mathgroup at smc.vnet.net
> Date: 2004/10/20 Wed AM 01:21:19 EDT
> To: mathgroup at smc.vnet.net
> Subject: [mg51521] [mg51499] conditionnal rule
> 
> hi all !!
> 
> I want to apply a rule under a certain condition. here is the example : 
> 
> myList = {{a, b}, {c, d}};
> 
> myList //. {a,x_}->{a,d}
> 
> apply this rule if Length[x]===1 (this means that x can not be a list)
> 
> I tried something like : 
> 
> myList //. {a_,x_}->{c,d}/;Length[x]===1
> 
> or
> 
> myList //. {a_,x_?Length[x]===1}->{c,d}/
> 
> but it does not work.
> 
> can someone help me ?
> 
> 


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