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Re: Re: Inverse of "PowerExpand"
And what do you think you need Together here for??? Andrzej Kozlowski On 28 Oct 2004, at 12:43, Peter Valko wrote: > *This message was transferred with a trial version of CommuniGate(tm) > Pro* > res1 = PowerExpand[Log[a*b*b/c]] > > res2 = Log[Together[Exp[res1]]] > > > ??? > > > > > Karl_boehme_9 at msn.com (Klaus G) wrote in message > news:<clnf0f$ode$1 at smc.vnet.net>... >> PowerExpand[Log[a*b*b/c]] >> >> gives: >> >> Log[a] + 2 Log[b] - Log[c] >> >> Which Function will return the original "Log"? >> >> Klaus G. >