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Re: Re: Inverse of "PowerExpand"


And what do you think you need Together here for???

Andrzej Kozlowski


On 28 Oct 2004, at 12:43, Peter Valko wrote:

> *This message was transferred with a trial version of CommuniGate(tm) 
> Pro*
> res1 = PowerExpand[Log[a*b*b/c]]
>
> res2 = Log[Together[Exp[res1]]]
>
>
> ???
>
>
>
>
> Karl_boehme_9 at msn.com (Klaus G) wrote in message 
> news:<clnf0f$ode$1 at smc.vnet.net>...
>> PowerExpand[Log[a*b*b/c]]
>>
>> gives:
>>
>> Log[a] + 2 Log[b] - Log[c]
>>
>> Which Function will return the original "Log"?
>>
>> Klaus G.
>


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