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Re: Inverse of "PowerExpand"

  • To: mathgroup at smc.vnet.net
  • Subject: [mg51649] Re: Inverse of "PowerExpand"
  • From: p-valko at tamu.edu (Peter Valko)
  • Date: Wed, 27 Oct 2004 23:43:15 -0400 (EDT)
  • References: <clnf0f$ode$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com
res1 = PowerExpand[Log[a*b*b/c]] 

res2 = Log[Together[Exp[res1]]]


???




Karl_boehme_9 at msn.com (Klaus G) wrote in message news:<clnf0f$ode$1 at smc.vnet.net>...
> PowerExpand[Log[a*b*b/c]]
> 
> gives:
> 
> Log[a] + 2 Log[b] - Log[c]
> 
> Which Function will return the original "Log"?
> 
> Klaus G.
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