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ExpandAll Problem with Rules


The ExpandAll Help says...

ExpandAll[expr] expands out all products and integer powers in any part of expr. 

The following works...

a(b + c) == d(e + f) // ExpandAll

a b + a c == d e + d f

The following appears to work, but gives a strange error message.

a(b + c) -> d(e + f) // ExpandAll

General::argt: ExpandAll called with 0 arguments; 1 or 2 arguments are \
expected

a b + a c -> d e + d f

David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/ 




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