|
[Date Index]
[Thread Index]
[Author Index]
How to solve a simple Trig cofunction?
- To: mathgroup at smc.vnet.net
- Subject: [mg50500] How to solve a simple Trig cofunction?
- From: bfeeny at mac.com (Brian Feeny)
- Date: Wed, 8 Sep 2004 05:14:59 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
Lets say I have:
cos[X+4] = sin[3X+2]
What would be the proper way to solve the above, for X, in
Mathematica, with the answer in degrees?
I did this, but something tells me their has to be a better way:
NSolve[Cos[X Degree +4 Degree] = Sin[3 X Degree+2 Degree], X]
I mean, I wish i didn't have to enter "Degree"so many times, perhaps
their is a simple way to just tell it the whole thing is in Degree.
Additionally, is their a way to constrain the above to 90 > X > 0? I
tried doing like:
NSolve[Cos[X Degree +4 Degree] = Sin[3 X Degree+2 Degree], X /; 90
>X>0]
but that obviously is not the right way since that doesn't work.
Appreciate all the help.
Brian
Prev by Date:
sorry, but more q's on random numbers
Next by Date:
Two questions
Previous by thread:
Re: sorry, but more q's on random numbers
Next by thread:
Re: How to solve a simple Trig cofunction?
|