Re: Plot[f, {x,a,b] vs Plot[{f},[x,a,b]

• To: mathgroup at smc.vnet.net
• Subject: [mg50665] Re: Plot[f, {x,a,b] vs Plot[{f},[x,a,b]
• From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
• Date: Wed, 15 Sep 2004 07:54:45 -0400 (EDT)
• Organization: Universitaet Leipzig
• References: <ci8mdd\$bqa\$1@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Hi,

Evaluate[] work only if it is direct wrapped arraound the
function argument that you wish to Evaluate[]
and so in Plot[{Evaluate[__]},_] it has no influence on
the evaluation of the Plot[] arguments.

Regards
Jens

Derek wrote:
>
> I am getting different results when I use Plot[f, {x,a,b] vs
> Plot[{f},[x,a,b] (the difference being the {f}), where f is a fairly
> complex function. The difference is important because Plot[f] gives
> the correct results but I want to be able to plot multiple functions
> i.e. Plot[{f,y},{x,a,b}]
>
> My code is below; any comments appreciated.
>
> Derek
>
> -----
>
> Clear["Global`*"]
> R2 := R1 + \[Gamma] (qj2 + (n - 1)qJ2)
> P2 := (1 - R2 o\[Beta] )a -
>     b(qj2 + (n - 1)qJ2)
> revj2 := P2 qj2
> profitj2 := revj2 - c qj2 - oF
> profit2 := n profitj2
> CS2 := Integrate[(1 - R2)a - b s, {s, 0, n qj2}] - n revj2
> W2 := CS2 + profit2
>
> mqj2opt := qj2 /. Solve[(D[profitj2, qj2] /. qJ2 -> qj2) == 0, qj2]
> mW20A := Simplify[
>     W2  /. qJ2 -> qj2 /.  qj2 -> (mqj2opt /. o\[Beta] -> 1) /.
>       o\[Beta] -> 1]
> mneqmAA :=
>   n /. Last[
>       Simplify[Solve[(profitj2 /. qJ2 -> qj2 /.
>                   qj2 -> (mqj2opt /. o\[Beta] -> 1) /. o\[Beta] -> 1)
> == 0,
>           n]]]
> mW2AA := Simplify[mW20A /. n -> (mneqmAA) ]
>
> a = 1;
> b = 0.5;
> c = 0;
> oF = 0.1;
>
> Plot[Evaluate[mW2AA /. R1 -> 0], {\[Gamma], 0, 1}]
> Plot[{Evaluate[mW2AA /. R1 -> 0]}, {\[Gamma], 0, 1}]

```

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