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Re: Plot[f, {x,a,b] vs Plot[{f},[x,a,b]

  • To: mathgroup at smc.vnet.net
  • Subject: [mg50702] Re: [mg50640] Plot[f, {x,a,b] vs Plot[{f},[x,a,b]
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Fri, 17 Sep 2004 01:16:45 -0400 (EDT)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

Put the Evaluate around the list

Plot[Evaluate[{mW2AA /. R1 -> 0}], {?, 0, 1}];


Bob Hanlon

> 
> From: dgurney at stanford.edu (Derek)
To: mathgroup at smc.vnet.net
> Date: 2004/09/15 Wed AM 01:49:49 EDT
> To: mathgroup at smc.vnet.net
> Subject: [mg50702] [mg50640] Plot[f, {x,a,b] vs Plot[{f},[x,a,b]
> 
> I am getting different results when I use Plot[f, {x,a,b] vs
> Plot[{f},[x,a,b] (the difference being the {f}), where f is a fairly
> complex function. The difference is important because Plot[f] gives
> the correct results but I want to be able to plot multiple functions
> i.e. Plot[{f,y},{x,a,b}]
> 
> My code is below; any comments appreciated.
> 
> Derek
> 
> -----
> 
> Clear["Global`*"]
> R2 := R1 + \[Gamma] (qj2 + (n - 1)qJ2)
> P2 := (1 - R2 o\[Beta] )a - 
>     b(qj2 + (n - 1)qJ2)
> revj2 := P2 qj2
> profitj2 := revj2 - c qj2 - oF
> profit2 := n profitj2
> CS2 := Integrate[(1 - R2)a - b s, {s, 0, n qj2}] - n revj2
> W2 := CS2 + profit2 
> 
> mqj2opt := qj2 /. Solve[(D[profitj2, qj2] /. qJ2 -> qj2) == 0, qj2]
> mW20A := Simplify[
>     W2  /. qJ2 -> qj2 /.  qj2 -> (mqj2opt /. o\[Beta] -> 1) /.  
>       o\[Beta] -> 1]
> mneqmAA := 
>   n /. Last[
>       Simplify[Solve[(profitj2 /. qJ2 -> qj2 /. 
>                   qj2 -> (mqj2opt /. o\[Beta] -> 1) /. o\[Beta] -> 1)
> == 0, 
>           n]]]
> mW2AA := Simplify[mW20A /. n -> (mneqmAA) ]
> 
> 
> a = 1;
> b = 0.5;
> c = 0;
> oF = 0.1;
> 
> Plot[Evaluate[mW2AA /. R1 -> 0], {\[Gamma], 0, 1}]
> Plot[{Evaluate[mW2AA /. R1 -> 0]}, {\[Gamma], 0, 1}]
> 
> 


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