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Re: Plot[f, {x,a,b] vs Plot[{f},[x,a,b]
*To*: mathgroup at smc.vnet.net
*Subject*: [mg50702] Re: [mg50640] Plot[f, {x,a,b] vs Plot[{f},[x,a,b]
*From*: Bob Hanlon <hanlonr at cox.net>
*Date*: Fri, 17 Sep 2004 01:16:45 -0400 (EDT)
*Reply-to*: hanlonr at cox.net
*Sender*: owner-wri-mathgroup at wolfram.com
Put the Evaluate around the list
Plot[Evaluate[{mW2AA /. R1 -> 0}], {?, 0, 1}];
Bob Hanlon
>
> From: dgurney at stanford.edu (Derek)
To: mathgroup at smc.vnet.net
> Date: 2004/09/15 Wed AM 01:49:49 EDT
> To: mathgroup at smc.vnet.net
> Subject: [mg50702] [mg50640] Plot[f, {x,a,b] vs Plot[{f},[x,a,b]
>
> I am getting different results when I use Plot[f, {x,a,b] vs
> Plot[{f},[x,a,b] (the difference being the {f}), where f is a fairly
> complex function. The difference is important because Plot[f] gives
> the correct results but I want to be able to plot multiple functions
> i.e. Plot[{f,y},{x,a,b}]
>
> My code is below; any comments appreciated.
>
> Derek
>
> -----
>
> Clear["Global`*"]
> R2 := R1 + \[Gamma] (qj2 + (n - 1)qJ2)
> P2 := (1 - R2 o\[Beta] )a -
> b(qj2 + (n - 1)qJ2)
> revj2 := P2 qj2
> profitj2 := revj2 - c qj2 - oF
> profit2 := n profitj2
> CS2 := Integrate[(1 - R2)a - b s, {s, 0, n qj2}] - n revj2
> W2 := CS2 + profit2
>
> mqj2opt := qj2 /. Solve[(D[profitj2, qj2] /. qJ2 -> qj2) == 0, qj2]
> mW20A := Simplify[
> W2 /. qJ2 -> qj2 /. qj2 -> (mqj2opt /. o\[Beta] -> 1) /.
> o\[Beta] -> 1]
> mneqmAA :=
> n /. Last[
> Simplify[Solve[(profitj2 /. qJ2 -> qj2 /.
> qj2 -> (mqj2opt /. o\[Beta] -> 1) /. o\[Beta] -> 1)
> == 0,
> n]]]
> mW2AA := Simplify[mW20A /. n -> (mneqmAA) ]
>
>
> a = 1;
> b = 0.5;
> c = 0;
> oF = 0.1;
>
> Plot[Evaluate[mW2AA /. R1 -> 0], {\[Gamma], 0, 1}]
> Plot[{Evaluate[mW2AA /. R1 -> 0]}, {\[Gamma], 0, 1}]
>
>
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