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MathGroup Archive 2004

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Re: anyone else have same problems? partition grahics

  • To: mathgroup at smc.vnet.net
  • Subject: [mg50688] Re: [mg50637] anyone else have same problems? partition grahics
  • From: "David Park" <djmp at earthlink.net>
  • Date: Fri, 17 Sep 2004 01:15:55 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

Sean,

Do you mean...

Needs["Graphics`Graphics`"]

g = Partition[{PieChart[{.2, .3, .1}, DisplayFunction ->
Identity], PieChart[{.2, .3, .1}, PieExploded -> All,
DisplayFunction ->
Identity], PieChart[{.2, .3, .1}, PieExploded -> {{3, .2}},
DisplayFunction -> Identity]}, 1]

Show[GraphicsArray[g]]


David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/ 

From: sean kim [mailto:sean_incali at yahoo.com]
To: mathgroup at smc.vnet.net


Hello group, 

I've been trying to get this to work but apparently
this works on mac but not on windows? or is it just
me? 


g = Partition[{PieChart[{.2,.3,.1}, DisplayFunction->
Identity], PieChart[{.2,.3,.1},PieExploded->All,
DisplayFunction->
Identity],PieChart[{.2,.3,.1},PieExploded->{{3,.2}},
DisplayFunction-> Identity]}, 2]
        
DisplayTogetherArray[g, DisplayFunction->
$DisplayFunction ]

above produces a blank GraphicsArray object. 

where as 

g = Partition[{PieChart[{.2, .3, .1}, DisplayFunction
-> Identity], PieChart[{.2, .3, .1}, PieExploded ->
All, DisplayFunction -> Identity], PieChart[{.2, .3,
.1}, PieExploded -> {{3, .2}}, DisplayFunction ->
Identity], PieChart[{.2, .3, .1}, PieExploded -> {{3,
.2}}, DisplayFunction -> Identity]}, 2]

Show[GraphicsArray[g]]

works.  

I do not understand what's going on here? 


thanks in advance for any insights. 

sean 





		
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