Re: Expanding a Square Root
- To: mathgroup at smc.vnet.net
- Subject: [mg50826] Re: [mg50813] Expanding a Square Root
- From: DrBob <drbob at bigfoot.com>
- Date: Wed, 22 Sep 2004 04:52:04 -0400 (EDT)
- References: <200409220411.AAA18714@smc.vnet.net>
- Reply-to: drbob at bigfoot.com
- Sender: owner-wri-mathgroup at wolfram.com
>> Expand[(44+9*SQRT(23))^2] yields >> 3799 + 792*SQRT(23) No, in Mathematica it's Expand[(44 + 9*Sqrt[23])^2] 3799 + 792*Sqrt[23] You could do this: (44 + 9*Sqrt[23])^2 Sqrt[%] (44 + 9*Sqrt[23])^2 44 + 9*Sqrt[23] or this: Expand[(44 + 9*Sqrt[23])^2] FullSimplify[Sqrt[%]] 3799 + 792*Sqrt[23] 44 + 9*Sqrt[23] Bobby On Wed, 22 Sep 2004 00:11:32 -0400 (EDT), Jim Dars <jim-dars at comcast.net> wrote: > Hi All, > > I should point out that I use Mathematica 4.0 infrequently, thus I may be > missing the obvious. My problem is as follows: > > In the following I use the square root sign from the palette for SQRT > Expand[(44+9*SQRT(23))^2] yields > 3799 + 792*SQRT(23) > > I now wish to take the square root of 3799 + 792*SQRT(23) to return to my > original expression. However > > Expand[SQRT(3799 + 792*SQRT(23))] merely yields > > [SQRT(3799 + 792*SQRT(23))] > > What is the proper command to make SQRT(3799 + 792*SQRT(23)) yield > 44+9*SQRT(23) > > Best wishes, Jim > > > > > -- DrBob at bigfoot.com www.eclecticdreams.net
- References:
- Expanding a Square Root
- From: "Jim Dars" <jim-dars@comcast.net>
- Expanding a Square Root