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MathGroup Archive 2004

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Re: Expanding a Square Root

  • To: mathgroup at smc.vnet.net
  • Subject: [mg50826] Re: [mg50813] Expanding a Square Root
  • From: DrBob <drbob at bigfoot.com>
  • Date: Wed, 22 Sep 2004 04:52:04 -0400 (EDT)
  • References: <200409220411.AAA18714@smc.vnet.net>
  • Reply-to: drbob at bigfoot.com
  • Sender: owner-wri-mathgroup at wolfram.com

>> Expand[(44+9*SQRT(23))^2]  yields
>> 3799 + 792*SQRT(23)

No, in Mathematica it's

Expand[(44 + 9*Sqrt[23])^2]
3799 + 792*Sqrt[23]

You could do this:

(44 + 9*Sqrt[23])^2
Sqrt[%]

(44 + 9*Sqrt[23])^2
44 + 9*Sqrt[23]

or this:

Expand[(44 + 9*Sqrt[23])^2]
FullSimplify[Sqrt[%]]

3799 + 792*Sqrt[23]
44 + 9*Sqrt[23]

Bobby

On Wed, 22 Sep 2004 00:11:32 -0400 (EDT), Jim Dars <jim-dars at comcast.net> wrote:

> Hi All,
>
> I should point out that I use Mathematica 4.0 infrequently, thus I may be
> missing the obvious.  My problem is as follows:
>
> In the following I use the square root sign from the palette for SQRT
> Expand[(44+9*SQRT(23))^2]  yields
> 3799 + 792*SQRT(23)
>
> I now wish to take the square root of  3799 + 792*SQRT(23) to return to my
> original expression.  However
>
> Expand[SQRT(3799 + 792*SQRT(23))] merely yields
>
> [SQRT(3799 + 792*SQRT(23))]
>
> What is the proper command to make SQRT(3799 + 792*SQRT(23)) yield
> 44+9*SQRT(23)
>
> Best wishes, Jim
>
>
>
>
>



-- 
DrBob at bigfoot.com
www.eclecticdreams.net


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