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MathGroup Archive 2004

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Re: Hyperbolic function identity

  • To: mathgroup at
  • Subject: [mg50945] Re: [mg50932] Hyperbolic function identity
  • From: "Maxim A. Dubinnyi" <maxim at>
  • Date: Wed, 29 Sep 2004 03:15:07 -0400 (EDT)
  • References: <>
  • Sender: owner-wri-mathgroup at

This works correctly:

FullSimplify[TrigToExp[ArcCosh[1+(z^2)/2]-2*ArcSinh[z/2]], z > 0]

It looks like that mathematica works better with logarithms and 
exponents then with trigonometric functions.

Carlos Felippa wrote:

>   FullSimplify[ArcCosh[1+z^2/2]-2*ArcSinh[z/2],z>0];
>does not evaluate to 0?

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