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Re: Hyperbolic function identity


expr = ArcCosh[1+z^2/2]-2*ArcSinh[z/2];

FullSimplify[TrigToExp[expr], z>0]

0


Bob Hanlon

> 
> From: carlos at colorado.edu (Carlos Felippa)
To: mathgroup at smc.vnet.net
> Date: 2004/09/28 Tue AM 12:58:52 EDT
> To: mathgroup at smc.vnet.net
> Subject: [mg50947] [mg50932] Hyperbolic function identity
> 
> Why 
> 
>    FullSimplify[ArcCosh[1+z^2/2]-2*ArcSinh[z/2],z>0];
> 
> does not evaluate to 0?
> 
> 


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