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Re: Hyperbolic function identity

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  • Subject: [mg50973] Re: Hyperbolic function identity
  • From: carlos at (Carlos Felippa)
  • Date: Thu, 30 Sep 2004 04:52:21 -0400 (EDT)
  • References: <cjasqk$ns0$>
  • Sender: owner-wri-mathgroup at

carlos at (Carlos Felippa) wrote in message news:<cjasqk$ns0$1 at>...
> Why 
>    FullSimplify[ArcCosh[1+z^2/2]-2*ArcSinh[z/2],z>0];
> does not evaluate to 0?

My apologies for the wording of the question.  Of course I know all
those coaching tricks and gyrations. I have been using them since
1994, when I began with Mathematica 2.2 (which did not even had

I should have worded it like this: why is FullSimplify unable to
perform its stated function from the data given, which is sufficient
to carry out the reduction?   Why are crutches like TrigToExp needed?

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