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Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg55819] Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?
*From*: APC <caraman48 at yahoo.com>
*Date*: Thu, 7 Apr 2005 05:09:58 -0400 (EDT)
*References*: <d3041u$ndm$1@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
Abs[(1+I)]=Sqrt[2]
Abs[(1+I)/Sqrt[2]]=1
it's just like normalizing a vector.
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