Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2005
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2005

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg55838] Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?
  • From: "Peltio" <peltio at trilight.zone>
  • Date: Thu, 7 Apr 2005 05:10:47 -0400 (EDT)
  • References: <d3041u$ndm$1@smc.vnet.net>
  • Reply-to: "Peltio" <peltioNOSPAM at despammed.com.invalid>
  • Sender: owner-wri-mathgroup at wolfram.com

"Matt" wrote

>I realize that (1 + I)/sqrt(2) is in the same direction as (1 + I), but
>why did Mathematica change it to the more 'strange' form?

The 'stranger' form is that of a versor.
I guess Mathematica has reduced your input to a 'normal form', that is a uniquely
defined representation of a certain quantity (the direction, in this case).
This is useful for several reasons, the most important being comparing
different objects of the same kind.

cheers,
Peltio
--
Invalid address in reply-to. Crafty demunging required to mail me.


  • Prev by Date: SetDirectory, Import
  • Next by Date: Re: Op-codes in CompiledFunction
  • Previous by thread: Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?
  • Next by thread: Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?