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MathGroup Archive 2005

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confusion about Thread[]

  • To: mathgroup at smc.vnet.net
  • Subject: [mg56007] confusion about Thread[]
  • From: Torsten Coym <torsten.coym at eas.iis.fraunhofer.de>
  • Date: Wed, 13 Apr 2005 01:10:46 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

Hi group,

given three lists

wLst = {w1, w2, w3}
zLst = {z1, z2, z3}
cLst = {c1, c2, c3}

with each element representing a boolean value I want to calculate a 
list of the same function applied to the corresponding elements of wLst, 
zLst, cLst respectively. While the expression


Thread[Thread[wLst && zLst] || Thread[wLst && cLst] ||
    Thread[zLst && cLst]]


{(w1 && z1) || (w1 && c1) || (z1 && c1), (w2 && z2) || (w2 && c2) ||
    (z2 && c2), (w3 && z3) || (w3 && c3) || (z3 && c3)}

does exactly what I want, I wonder why the following approach using a 
pure function with three input arguments and a single call of Thread[] 
does not give the desired result:


Thread[((#1 && #2) || (#1 && #3) || (#2 && #3) & )[wLst, zLst, cLst]]

({w1, w2, w3} && {z1, z2, z3}) || ({w1, w2, w3} && {c1, c2, c3}) ||
   ({z1, z2, z3} && {c1, c2, c3})

although

((#1 && #2) || (#1 && #3) || (#2 && #3) & )[w1, z1, c1]

(w1 && z1) || (w1 && c1) || (z1 && c1)

implements the desired logical expression and


Thread[f[wLst, zLst, cLst]]

{f[w1, z1, c1], f[w2, z2, c2], f[w3, z3, c3]}

works the way I expect it.


It seems I am a bit disconnected here ...

Torsten


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