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Re: Convert to hypergeometric function
- To: mathgroup at smc.vnet.net
- Subject: [mg62806] Re: Convert to hypergeometric function
- From: Paul Abbott <paul at physics.uwa.edu.au>
- Date: Mon, 5 Dec 2005 13:41:18 -0500 (EST)
- Organization: The University of Western Australia
- References: <dn0vfg$8k3$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
In article <dn0vfg$8k3$1 at smc.vnet.net>, bd satish <bdsatish at gmail.com>
wrote:
> How do you express the following function functions in terms of
> the hypergeometric function ?
>
> ExponentialIntegral Ei(x)
Go to http://functions.wolfram.com/GammaBetaErf/ExpIntegralEi/ and click
on the "Representations through more general functions" link. There you
will find that a number of possible representations including
ExpIntegralEi[z] == z HypergeometricPFQ[{1, 1}, {2, 2}, z] +
(1/2) (Log[z] - Log[1/z]) + EulerGamma
> LogarithmicIntegral Li(x)
At http://functions.wolfram.com/06.36.26.0001.01 you will find that
LogIntegral[z] == Log[z] HypergeometricPFQ[{1, 1}, {2, 2}, Log[z]] +
(1/2) (Log[Log[z]] - Log[1/Log[z]]) + EulerGamma
> Trigonometric functions:
> sin(x) arcsin(x)
> cos(x) arccos(x)
> tan(x) arctan(x)
> cot(x) arccot(x)
> sec(x) arcsec(x)
> cosec(x) arccosec(x)
Similar answers for all these case. E.g., at
http://functions.wolfram.com/01.10.26.0001.01 you will find that
Csc[z] == 1/(z HypergeometricPFQ[{}, {3/2}, -(z^2/4)])
> Similarly the hyperbolic functions : sinh(x) cosh(x) tanh(x) ;;;
> arcsinh(x) arccosh(x) arctanh(x)
>
> The logarithmic function: log(1+x) or log(x)
> the gamma function : gamma(n)
> the lambert function : lambertW(n,x)
>
> PLEASE provide the solutions for all the above cases (if possible)
I expect that I don't need to go into details here ...
Cheers,
Paul
_______________________________________________________________________
Paul Abbott Phone: 61 8 6488 2734
School of Physics, M013 Fax: +61 8 6488 1014
The University of Western Australia (CRICOS Provider No 00126G)
AUSTRALIA http://physics.uwa.edu.au/~paul
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